(1-x)(x^2-7x+10)+6-3x=0

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Solution for (1-x)(x^2-7x+10)+6-3x=0 equation: 



(1-x)(x^2-7x+10)+6-3x=0

We add all the numbers together, and all the variables

(-1x+1)(x^2-7x+10)-3x+6=0

We add all the numbers together, and all the variables

-3x+(-1x+1)(x^2-7x+10)+6=0

We move all terms containing x to the left, all other terms to the right

-3x+(-1x+1)(x^2-7x+10)=-6

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